(3) For the number $(3+\sqrt{8})^{2 n}\left(n \in \mathbf{N}^{*}\right.$ and $\left.n \geqslant 2009\right)$, let $[x]$ be the integer part of $x$. Then the remainder when $\left[(3+\sqrt{8})^{2 n}\right]$ is divided by 8 is $(\quad)$.
(A) 1
(B) 3
(C) 4
(D) 7