2. As shown in Figure 1, $P$ is a point inside $\triangle A B C$, and satisfies $\boldsymbol{A P}=$ $\frac{2}{5} A B+\frac{1}{5} A C$. Then the ratio of the area of $\triangle P B C$ to the area of $\triangle A B C$ is ( ).
(A) $\frac{1}{2}$
(B) $\frac{2}{3}$
(C) $\frac{3}{5}$
(D) $\frac{2}{5}$