6. Given the sequence $\left\{a_{n}\right\}$ satisfies $a_{0}=1, a_{1}=1, a_{n}=a_{n-1}+\frac{a_{n-1}^{2}}{a_{n-2}}(n \geqslant 2)$; the sequence $\left\{b_{n}\right\}$ satisfies $b_{0}=1, b_{1}=3, b_{n}=b_{n-1}+\frac{b_{n-1}^{2}}{b_{n-2}}(n \geqslant 2)$. Then $\frac{b_{32}}{a_{32}}=$ $\qquad$