In the six-digit number $1 A B C D E$, each letter represents a digit. Given that $1 A B C D E \times 3=A B C D E 1$, the value of $A+B+C+D+E$ is
(A) 29
(B) 26
(C) 22
(D) 30
(E) 28

Part C: Each correct answer is worth 8.