2. Given a divisor (not 0) and a dividend, we can always find a quotient and a remainder that satisfy
dividend $=$ divisor $\times$ quotient + remainder
where, $0 \leq$ remainder < divisor. This is division with a remainder. When the remainder is 0, we also say the divisor divides the dividend evenly, or the divisor is a factor of the dividend (the dividend is a multiple of the divisor).
Please write down all natural numbers greater than 1 and not exceeding 88 that can be divided evenly by 6: $\qquad$