1. Given $\sin 18^{\circ}=\frac{-1+\sqrt{5}}{4}$. Then
$$
\begin{array}{l}
a=\sin 2007^{\circ}, b=\cos 2007^{\circ}, \\
c=-1+\tan 2007^{\circ}, \\
d=\frac{\sin 2007^{\circ}+\cos 2007^{\circ}}{\sqrt{2}}
\end{array}
$$

the size relationship is ( ).
(A) $b<a<d<c$
(B) $b<a<c<d$
(C) $c<b<a<d$
(D) $d<b<c<a$