<p>3/10/2008 = 1822556159</p>

<p>2/10/2008 = 1822523391</p>

<p>1/10/2008 = 1822490623</p>

<p>30/09/2008 = 1822392319</p>

<p>29/09/2008 = 1822359551</p>

<p>This is all the information that I know at the current time. </p>

<p>Dates increment by 32768 except when changing month when the increment is 32768 x 2 (65536).</p>

<p>Has anyone seen this binary date format and how can I extract the correct date?</p>

<hr>

<p>It is possible that the remaining portion of the date is for time (hours, minutes, seconds)</p>

September 30th 2008
```
```
1822392319 = 0x6c9f7fff
0x6c = 108 = 2008 (based on 1900 start date)
0x9 = 9 = September
0xf7fff - take top 5 bits = 0x1e = 30
```
```
October 1st 2008
```
```
1822490623 = 0x6ca0ffff
0x6c = 108 = 2008
0xa = 10  = October
0x0ffff  - take top 5 bits = 0x01 = 1
```
```
It's anyone's guess what the remaining 15 one-bits are for, if anything.
EDIT:  by take top 5 bits I mean:
```
```
day_of_month = (value >> 15) & 0x1f
```
```
Similarly:
```
```
year = (value >> 24) & 0xff + 1900
month = (value >> 20) & 0x0f
```
```