<p>I've been reading up on conditional-style expressions in ruby. However I came across one I couldn't quite understand to define the classic FizzBuzz problem. I understand the FizzBuzz problem and even wrote my own before finding the following quick solution utilising the ternary operator. If someone can explain to me how this chain works to satisfy the FizzBuzz problem it would be very much appreciated :)</p>

<pre><code>for i in 0...100
  puts i%3==0 ? i%5==0 ? "FizzBuzz" : "Buzz" : i%5==0 ? "Fizz" : i
end
</code></pre>

Some parentheses might help:
```
```
puts (i%3 == 0) ? ((i%5 == 0) ? "FizzBuzz" : "Buzz") : ((i%5 == 0) ? "Fizz" : i)
```
```
So, if i is divisible by 3, then it checks whether i is also divisible by 5. If so, it prints "FizzBuzz" otherwise just "Buzz". If i is not divisible by three, then it checks divisibility by 5 again and prints "Fizz" if so, otherwise just i.