<p>Is there any method?
My computer is AMD64.</p>

<pre><code>::std::string str;
BOOL loadU(const wchar_t* lpszPathName, int flag = 0);
</code></pre>

<p>When I used: </p>

<pre><code>loadU(&amp;str);
</code></pre>

<p>the VS2005 compiler says:</p>

<pre><code>Error 7 error C2664:: cannot convert parameter 1 from 'std::string *__w64 ' to 'const wchar_t *'
</code></pre>

<p>How can I do it?</p>

If you have a std::wstring object, you can call
```
c_str()
```
on it to get a
```
wchar_t*
```
:
```
```
std::wstring name( L"Steve Nash" );
const wchar_t* szName = name.c_str();
```
```
Since you are operating on a narrow string, however, you would first need to widen it.  There are various options here; one is to use Windows' built-in
```
MultiByteToWideChar
```
routine.  That will give you an
```
LPWSTR
```
, which is equivalent to
```
wchar_t*
```
.